<span>How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size & the height is quadrupled?
Volume of an oblique cylinder = </span>π * r² * h
radius is reduced to 2/9 of its original size = r * 2/9 = (2r/9)
height is quadrupled = h * 4 = 4h
Volume of an oblique cylinder = π * (2r/9)² * 4h
Assume: r = 9 ; h = 10
V = π * 9² * 10 = 3.14 * 81 * 10 = 2,543.40
V = π * (2²) * (10*4) = 3.14 * 4 * 40 = 502.4
The new volume decrease and is almost equivalent to 20% of the original volume.
Answer:
it would be b for 1 since 7 would be negative and the 3 would be positive
<span>(-1/2)(4)(-2)(7y)(-1)
Just start multiplying!
-1/2 * 4 = -2
-2 * -2 = 4
4 * 7y = 28y
28y * -1 = -28y
Since that's not an option I suspect you're missing an x.</span>
1. Multiply length times width as if they were integer number:
Now place the decimal point. To do it we have to keep in mind that the result will have as many decimals as the sum of the decimals of each number. In this case, only the width had one decimal, it means that the result will only have one decimal:
It's might be.....180,000 I'm sure
