the temperature in Portland, Marine, reached -3.5ºF one day last winter. Between with two integers does the temperature lie?

Mathematics

1 answer:

Rzqust [24]3 years ago

3 0

It lies between -3 and -4.

An integer is any whole number, positive or negative.

You might be interested in

PLEASE HELP???!!!!!

Likurg_2 [28]

We'll use the Pythagorean Theorem
130^2 = side^2 +50^2
side ^ 2 = 16,900 -2,500
side ^ 2 = 14,400
side = square root (14,400)
side = 120 feet

4 0

3 years ago

Read 2 more answers

Sidh is making fruit salad. His recipe calls for 3/4 pound of watermelon. He wants

Dvinal [7]

Answer:

3/8

Step-by-step explanation:

3/4 x 1/2 = 3/8

6 0

3 years ago

What is the solution of the equations y=-x and y=-14X+1?

oksano4ka [1.4K]

The solution as in where do they intersect? if so, it would be 0.0769 and -0.0769

4 0

3 years ago

1. Lựa chọn yêu cầu cần đạt trong Chương trình Giáo dục phổ thông môn Toán 2018 lớp 3, xây dựng một công cụ sử dụng trong đánh g

maks197457 [2]

Answer:

So basically you add x with 9 and you get 9x

3 0

3 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

3 years ago