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3 years ago

13

Adriana y Luisa fueron a la feria y decidieron subirse a la rueda de la fortuna. Si el diámetro de la rueda es de 8 metros, ¿Qué

recorrido hicieron dando una vuelta completa? Considera Pi= 3.14

1 answer:

sashaice [31]3 years ago

6 0

Answer:

Translation?

Step-by-step explanation:

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Roni's parents are planning a vacation. They found a cabin to rent for $75 a day with no deposit. They also found a hotel that w

densk [106]

Answer:

The answer is C

Step-by-step explanation:

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3 years ago

An experiment consists of drawing 1 card from a standard 52-card deck. let e be the event that card drawn is a 33. find p(e).

Dafna1 [17]

1 out of 52. So 1/52 equals some decimal. Plug in calc.

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2 years ago

HELP ASAP 30 POINTS GIVEN

Sati [7]

The slope of JK is -3/7
The slope of LK is 2
The slope of ML is -3/7
The slope of MJ is 2
Quadrilateral JKLM is a parallelogram because both pairs of opposite sides are parallel. YOU'RE WELCOME :D

4 0

3 years ago

Read 2 more answers

(6+23) x (32-25) + 72<br> I just need to see what the answer is to check my work

Vlad1618 [11]

Answer:

275

Step-by-step explanation:

6+23=29 and 32-25=7

29 x 7 = 203

203 + 72 = 275

The final answer is 275.

Hope this helps!

7 0

2 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago