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1 answer:
<h3>Answer:</h3>
A) Shading is below the line y=2x-7, and that line is dashed. Shading is above the line y=-x/2+3, and that line is solid. The solution area is where the shading overlaps.
B) No. It fails to satisfy the second inequality.
<h3>Step-by-step explanation:</h3>Part A. The boundary line of the first inequality has a slope of +2 and a y-intercept of -7. Since allowed y-values are less than those on this line, the line is dashed and the shading is below the line. The solution space is shown with blue shading in the attachment.
The boundary line of the second inequality has a slope of -1/2 and a y-intercept of +3. Allowed values of y are equal to or greater than those on this line, so the line is solid and shading is above the line. The solution space is shown with green shading in the attachment.
The solution space is where the shaded areas overlap, generally to the upper right of the graph.
Part B. The point (3, -7) is in the shaded area for the first inequality, but not for the second. It does not meet the requirement for y ≥ -1/2x +3. You can see this when you substitute the point values:
-7 ≥ -1/2(3) +3 ⇒ -7 ≥ 3/2 ⇒ FALSE
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Answer:
(-5,0)
Step-by-step explanation:
In case when you tracking the finger across the line, at which there is an increase or decrease in y axis so this is we called intervals. Moreover, the interval notation is also necessary as it depicts the beginning and ending points. In this, the first number denotes the minimum number while the second number denotes the maximum number
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Answer:
(a) The confidence level desired by the researchers is 95%.
(b) The sampling error is 0.002 microcurie per millilitre.
(c) The sample size necessary to obtain the desired estimate is 25.
Step-by-step explanation:
The mean and standard deviation of the amount of the radioactive element, cesium-137 present in a sample of <em>n</em> = 16 lichen specimen are:
Now it is provided that the researchers want to increase the sample size in order to estimate the mean μ to within 0.002 microcurie per millilitre of its true value, using a 95% confidence interval.
The (1 - <em>α</em>)% confidence interval for population mean (μ) is:
(a)
The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.
In this case the researches wants to estimate the mean using the 95% confidence interval.
Thus, the confidence level desired by the researchers is 95%.
(b)
In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.
In case of the estimate of parameter using a confidence interval the sampling error is known as the margin of error.
In this case the margin of error is 0.002 microcurie per millilitre.
(c)
The margin of error is computed using the formula:
The critical value of <em>z</em> for 95% confidence level is:
*Use a <em>z</em>-table.
Thus, the sample size necessary to obtain the desired estimate is 25.