All categories

3 years ago

8,6,9,11,12,4,9,2 what is the mean the median and the mode and the range

Mathematics

1 answer:

ASHA 777 [7]3 years ago

6 0

Mean: 7.625
Mode: 9
Median: 8.5
Range: 10

You might be interested in

What two numbers add up to 6 and multiply to 12?

GuDViN [60]

Erm

x+y=6
xy=12

x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
$x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

$x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}$
$x= \frac{6+/- \sqrt{36-48} }{2}$
$x= \frac{6+/- \sqrt{-12} }{2}$
$x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}$
$x= \frac{6+/- (i)(2\sqrt{3}) }{2}$
$x= \frac{6+/- 2i\sqrt{3} }{2}$
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho

7 0

3 years ago

Which relation is a function ?

Cloud [144]

Y is the function of x so there are two things called Input and output

3 0

3 years ago

Help me please I don’t have much time!!! I don’t understand this

xeze [42]

The answer is choice C

3 0

3 years ago

The measure of a vertex angle of an isosceles triangle is 120° and the length of a leg is 8 cm. Find the length of a diameter of

Goryan [66]

ANSWER

The length of a Diameter is 3.714

EXPLANATION

The circumscribed triangle is shown in the attachment.

We use the cosine ratio to find the altitude of the isosceles triangle.

$\cos(60 \degree) = \frac{altitude}{hypotenuse}$

$\cos(60 \degree) = \frac{altitude}{8}$

Altitude =8cos(60°)

Altitude=4cm

Let the upper half of the altitude be y cm.

Then the radius of the circle is (y-4)cm

The upper radius meets the tangent at right angles.

From the smaller right triangle,

$\sin(60 \degree) = \frac{4 - y}{y}$

$y\sin(60 \degree) = 4 - y$

$y\sin(60 \degree) + y= 4$

$(\sin(60 \degree) + 1)y= 4$

$y= \frac{4}{\sin(60 \degree) + 1}$

$y = 16 - 8 \sqrt{3}$

y=1.857

The diameter is 2y

$d = 32 - 16 \sqrt{3}$

=2(1.875)

The length of a Diameter is 3.714

7 0

3 years ago

Read 2 more answers

The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th

USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

$H_{0}$ : μ=523

$H_{a}$ : μ>523

The conclusion is failure to reject the null hypothesis.

This means that test statistic is lower than critical value. Therefore it is not significant, there is no significant evidence to accept the alternative hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0

3 years ago