Answer;
Two recessive alleles are the number of alleles that a person must have to have albinism.
Explanation;
When a trait is recessive, such as albinism, an individual must have two copies of a recessive allele to express that particular trait. Recessive alleles are denoted by a lowercase letter , such as b versus B. Only individuals with a bb genotye will express a recessive trait, hence, the offspring must receive one recessive trait from each parent to exhibit the recessive trait.
There is going to be a 25% chance of it being heterozygous unless both parents are heterozygous then if so you do happen to have to heterozygous parents it will be 100% heterozygous.
Answer:
The movement pursued social, legal, and political equality.
Explanation:
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Answer:
The answer is 60%.
Explanation:
Let's take the capıital letter L for the dominant long finger gene, and l for the recessive long finger gene.
The two heterozygous people with long fingers mate which means their genotypes are Ll or lL.
The probability of their first child having a heterozygous genotype is 50%. The probability of having dominant homozygous genotype LL is 25% and the probability of having recessive homozygous genotype ll is also 25%.
It is stated that the long finger trait is a recessive trait with 80% penetrance which means that even if the genotype suggests that the trait will be observable, it is only 80% of the time.
There is a 75% chance that their first child will inherit the recessive long finger trait gene l and with an 80% penetrance, the probability of the child having long fingers is 60%.
I hope this answer helps.
