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Step2247 [10]
3 years ago
6

To remain on the cheerleader squad, Leah must attend at least 3/5 of the study sessions offered. she attends 15 sessions. If Lea

h met the requirements, what is the least amount of study sessions offered
Mathematics
1 answer:
Ann [662]3 years ago
8 0
The denominator is supposed to be 15 so do 3/5x3=9/15
 So she must attend at least 9 classes
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A number a decreased by 7 is 2.
umka21 [38]

Answer:

9

Step-by-step explanation:

Let's first convert this to numbers. When a number is decreased by a certain amount, that is the same as saying that something is subtracted from it. Therefore:

a-7=2

Add 7 to both sides:

a-7+7=2+7

a=9

Hope this helps!

7 0
3 years ago
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Ejercicio 34 - College Board
NISA [10]
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3 years ago
The formula for the area of a square is A = sa, where s is the length of a side.
Sliva [168]

Answer:

\sqrt{400} = 20

Step-by-step explanation:

Since the sides of a square are equal, A = s x s so taking the square root of the square provides the length of each side

6 0
2 years ago
Solve the system of equations 2x-2y=-14 and 3x-y=-1 by combining the equations.
Veseljchak [2.6K]

The solution to the system of equations is x = 3 and y = 10

<h3>How to solve the equations?</h3>

The system is given as:

2x-2y=-14

3x-y=-1

Multiply (1) by 1 and (2) by 2

So, we have:

1(2x-2y=-14)

2(3x-y=-1 )

This gives

2x - 2y=-14

6x - 2y=-2

Subtract the equations

-4x = -12

Divide by -4

x = 3

Substitute x = 3 in 3x-y=-1

3(3)-y=-1

Evaluate

9 - y = -1

Solve for y

y = 10

Hence, the solution to the system of equations is x = 3 and y = 10

Read more about system of equations at:

brainly.com/question/12895249

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7 0
2 years ago
What is the volume of a hemisphere with a radius of 2.3m round to the nearest tenth of a cubic meter
kodGreya [7K]

Answer: 25.5 m^{3}

Step-by-step explanation:

If the volume of a sphere is

V=\frac{4}{3} \pi r^{3}

Where r=2.3 m is the radius

The volume of a hemisphere is half the volume of the total sphere:

V_{hemisphere}=\frac{V}{2}=\frac{\frac{4}{3} \pi r^{3}}{2}

V_{hemisphere}=\frac{2}{3} \pi r^{3}

Solving this equation:

V_{hemisphere}=\frac{2}{3} \pi (2.3 m)^{3}

Finally:

V_{hemisphere}=25.48m^{3} \approx 25.5 m^{3}

5 0
3 years ago
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