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2 years ago

What is the slopeOf a line that is perpendicular to a line who’s equation is 8y-5x=11

Mathematics

1 answer:

Anna35 [415]2 years ago

8 0

first off, let's put 8y - 5x = 11, in a slope-intercept form, so we can see what's its slope

$\bf 8y-5x=11\implies 8y=5x+11\implies y=\cfrac{5x+11}{8} \\\\\\ y=\stackrel{slope}{\cfrac{5}{8}}x+\cfrac{11}{8}$

so the slope of this line is 5/8, well then

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{5}{8}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{8}{5}}\qquad \stackrel{negative~reciprocal}{-\cfrac{8}{5}}}$

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Please Help!!

algol13

When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
$y < \frac{2}{3} x$
Choose a point in the lower or upper half plane created by the line
$y = \frac{2}{3} x$
The above line is the one which goes through the origin.

Now testing (1,0) yields,

$0 < \frac{2}{3} (1)$
That is,

$0 < \frac{2}{3}$
This statement is true. So we shade the lower half of
$y = \frac{2}{3} x$

For
$y \geqslant - x + 2$
We test for the origin because, it is not passing through the origin.

$0 \geqslant - (0) + 2$
This yields
$0 \geqslant 2$
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph

8 0

2 years ago

What is 1 1/3 as a improper fraction

Mumz [18]

Okay so for this all you have to do is add 1 to 1/3.

However, to do this you first need to convert 1 into a fraction.

1 = 3/3
3/3 + 1/3 = 4/3

Hope this helps :)

8 0

2 years ago

Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five l

Lynna [10]

Answer:

eh width = 103.5 inches

Step-by-step explanation:

x = width

Length = (x/2 - 5 )*6

so 384=x+3x-30

414=4x

x=414/4=103.5 inches

5 0

2 years ago

Solve for x.

andre [41]

Answer:

A cuz x+6 is double x-3 so divide them and equate it to 2 you'd get x+6 = 2x-6

12=2x-x

8 0

2 years ago

Having trouble w graphing :(

NISA [10]

6x/6=x>/= (=) 11/6

x=11/6 or about 1.8

the first important notation to remember when graphing inequalities is that the graph is going to face the way the inequality sign is pointing.

in this case, the sign is pointing right. now the second thing to remember is that an inequality sign with a line underneath it means that it is greater/equal to so the graph in which we fill will have be a closed circle

1) start the ray at ~1.8 and fill in the circle at the end of the ray then extend to its endpoint

that's all. you're graph now reads x is greater or equal to 11/6

3 0

2 years ago