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2 years ago

5a-a^2+15-3a-(a-1)^2 Simplify And show your work pls!

Mathematics

1 answer:

Roman55 [17]2 years ago

5 0

Answer:

$-2a^2+4a+14$

Step-by-step explanation:

$5a-a^2+15-3a-(a-1)^2$

$(a-1)^2$ = $(a-1)(a-1)$

$(a-1)(a-1)$ = $a^2-1a-1a+1$ = $a^2-2a + 1$

$5a-a^2+15-3a-(a^2-2a + 1)$

$-1(a^2-2a + 1)$ = $-a^2+2a -1$

$5a-a^2+15-3a-a^2+2a-1$

Now, we combine liked terms:

$(5a-3a+2a)+(-a^2-a^2)+(15-1)$

$4a-2a^2+14$

Rewrite your expression in stand form:

$-2a^2+4a+14$

Hope this helps!

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Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third

asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

$average=\frac{81+87+x}{3}$

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

$80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85$

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

$80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x$

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

$\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87$

This ine $72\leq x} \leq 87$ quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0

3 years ago

Games at a carnival cost $3. prizes awarded to winners cost $145.65. how many games must be played to make $50

stich3 [128]

Answer:

Step-by-step explanation:

3×1405 and $.65

8 0

3 years ago

3. Given ABCD ≅ FGHJ and mC = 9x - 7, mH = 5x + 13, find the value of x and the measures of angle C and angle H. Show all work

Bas_tet [7]

Since congruence and similarity for polygons is posted in a specific order, we know that angle A=angle F, side A=side F, die B=side G, and so on. Therefore, we have that angle C=angle H = 9x-7=5x+13. Subtracting 5x from both sides to separate the x using the subtraction property of equality, we get 4x-7=13. Next, we can add 7 to both sides to get 4x=20, and divide both sides by 4 to isolate the x and get x=5. Plugging that into angle C or angle H, we get that 9x-7=9*5-7=45-7=38=5*5+13.

Feel free to ask further questions!

5 0

3 years ago

9x-22=23+4x I don't understand how to do this

anygoal [31]

9x-22=23+4x Now you subtract 4x from both sides to get the variable on one side.. 5x-22=23 Now solve as you would solve a 2 step equation. 5x=45 Divide both sides by 5 to get the variable by itself. x=9

4 0

3 years ago

A drawer contains 4 white socks, 5 black socks, and 3 brown socks. Find the probability that...

IRINA_888 [86]

Answer:

5/12

7/12

125/36 = 3,47%

50/11 = 4,54%

Step-by-step explanation:

Probability a black sock is selected when a person chooses 1 sock = 5/12

Probability a white or brown sock is selected when a person chooses 1 sock =

7/12

Probability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%

Pobability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%

3 0

3 years ago