The problem says that <span>Brandon sights a helicopter above a building that is 200 feet away at an angle of elevation of 30 degrees. So, you can calculate the height asked, by following this procedure:
</span>
Tan(α)=Opposite leg/Adjacent leg
α=30°
Opposite leg=x
Adjacent leg=200 feet
When you substitute these values into the formula above (Tan(α)=Opposite leg/Adjacent leg), you have:
Tan(α)=Opposite leg/Adjacent leg
Tan(30°)=x/200
You must clear "x":
x=200xTan(30°)
Therefore, the value of "x" is:
x=115 feet
<span>
How high above the ground the is the helicopter?
The answer is: 115 feet</span>
Answer:

Step-by-step explanation:
Using the midpoint formula,
, we can find the coordinates that represents the position of the ship at noon.
Let
(given on the coordinate plane)
(given also)
Plug in the values into the formula and solve as follows:




Position of the ship at noon is best represented at 
Answer:
2 days late
Step-by-step explanation:
Answer:
26 seats
Step-by-step explanation:
10+10=20 +6 =26
F(-3) = -2(-3)^2 - 5(-3) + 4 = -2(9) + 15 + 4 = -18 + 19 = 1