Uhhh , what are we suppose to answer here ?
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
Answer:
79
Step-by-step explanation:
so you dont move anything,
If you decrease number by 50% of that number you are basically dividing with 2 hence the answer is 15.
2n² + n + 1
<u>Explanation:</u>
The sequence is 4, 11, 22, 37
Difference between: 7, 11, 15
The first differences are 7, 11, 15, and the second differences are 4.
Since half of 4 is 2, then the first term will be 2n^2.
Subtracting 2n² from the sequence gives 2, 3, 4, 5 which has nth term n + 1.
Therefore the final answer is 2n² + n + 1
