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ivolga24 [154]
3 years ago
14

Ten times a number increased by eighty four equals 194. what is the number

Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0

Answer: x = 11

Step-by-step explanation:

10x+84=194

10x = "10 times a number"

+84 = "increased by eighty four"

=194 = "equals 194"

10x+84=194

Subtract 84

10x = 110

Divide by 10

x = 11

<em>Hope it helps <3</em>

yarga [219]3 years ago
4 0

Answer:

The number is 11

Step-by-step explanation:

Represent the number by n.

Then:  10n + 84 = 194.

Subtracting 84 from both sides, we get:  10n = 110, and so:

n = 110/10 = 11

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Suppose f′(6)=5 and g′(6)=7. <br> Find h′(6) where h(x)=4f(x)+5g(x)+1.
Nimfa-mama [501]

The value of the derivative of functions h'(6) as requested in the task content is; 55.

<h3>What is the value of h'(6)?</h3>

Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.

Hence, the derivative of h(x) can be evaluated as;

h'(x)=4f'(x)+5g'(x)

On this note, by substitution, it follows that;

h'(6)=4(5)+5(7)

h'(6) = 55.

Read more on functions;

brainly.com/question/6561461

#SPJ1

3 0
2 years ago
Is this right ? Plz help mee
sasho [114]
6.32 is the final answer! :)
6 0
3 years ago
Read 2 more answers
Find the product -3,-4.-2.5
Assoli18 [71]

Answer:

-30

Step-by-step explanation:

-3(-4)(-2.5)

Apply rule -(-a) = a

=-3*4*2.5

Multiply the numbers: 3*4*2.5=30

=-30

6 0
3 years ago
Please answer correctly !!!!!!!! Will mark brianliest !!!!!!!!!!!
nexus9112 [7]

Answer:

x=6

Step-by-step explanation:

h(x) = -( x-2)^2 +16

We want when h(x) = 0

0 = -( x-2)^2 +16

Subtract 16 from each side

-16  = -( x-2)^2 +16-16

-16 = -( x-2)^2

Divide by -1

16= ( x-2)^2

Take the square root of each side

±sqrt(16) = sqrt(( x-2)^2 )

±4 = x-2

Add 2 to each sdie

2 ±4 = x-2+2

2+4 = x     2-4 =x

6 =x           -2 =x

since time cannot be negative

x=6

4 0
3 years ago
7x-2y=16 11x+6y=32.3<br>how to solve this math problem​
Aneli [31]

Answer:

Step-by-step explanation:

These types of equations are called simultaneous equations and the method we can use to solve these type of equations is either Substitution, Elimination and Graphing.

We use substitution here because it is easier.

Equation 1

7x-2y=16

Equation 2

11x+6y=32.3

Lets take equation 1

7x-2y=16\\7x=16+2y\\x=\frac{16+2y}{7}

This is our equation 3 , now put it inside equation 2.

11x+6y=32.3\\11(\frac{16+2y}{7} )+6y=32.3\\\frac{176+22y}{7} +6y=32.3\\\frac{176+22y+42y}{7}=32.3\\176+22y+42y=226.1 \\\\42y+22y=226.1-176\\64y=50.1\\y=\frac{50.1}{64} \\y=0.783\\

We found the value of y , now to find the value of x insert the value of y in equation 3

x=\frac{16+2y}{7}\\x=\frac{16+2(0.783)}{7} \\x=\frac{16+1.566}{7}\\x=\frac{17.566}{7}\\x=2.509

Solved ! See the attached image on both the straight line graphs i have attached for better understanding. Where both the lines intersect each other is our value of (x , y) respectively.

6 0
3 years ago
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