Answer:
Why are you timesing me IDK
Step-by-step explanation:
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Step-by-step explanation:
Remember SOH-CAH-TOA:
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
The side adjacent to W is 4. The side opposite of W is 3. The hypotenuse is 5.
Therefore:
Sine = 3 / 5
Cosine = 4 / 5
Tangent = 3 / 4
Find<span> the </span>Equation<span> of a Line Given That You </span>Know<span> Its </span>Slope<span> and Y-Intercept. The </span>equation<span> of a line is usually written as y=mx+b where m is the </span>slope<span> and b is the y-intercept. If you </span>know<span> the </span>slope<span> (m) any y-intercept (b) of a line, this page will show you </span>how to find<span> the </span>equation<span> of the line. thats the method i use</span>