(not sure )
my method
let projection of b onto line dq be M
BM is 2r
then let the remaining angle ( right) be K
in triangle BMK ,
MK = 29-5-r
By Pyth. theorem ,
23^2 = (2r)^2+(29-5-r)^2
529=4r^2+576-48r+r^2
5r^2-48r+47=0
r = 8.493237063 or 1.106762937(rejected)
6.r_xaxis=(x,-y)
7.first option
Step-by-step explanation:
6b < 42 or 4b + 12 > 8
6b < 42
= 6b/6 < 42/6
= b < 7
4b + 12 > 8
=4b - 12 + 12 < -12+8
= 4b > - 12 + 8
= 4b > -4
= 4b/4 = -4/4
b > -1
so
7 > b > -1
Answer:
C &A
Step-by-step explanation:
Just by analyzing the problem you can match up the answers
Solve the problem in your head and the closest answer to that is the answer
Answer:
131.3 miles
Step-by-step explanation:
The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.
Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:
d₁ + d₂ = 374 miles (1)
Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence
For car c:
2x = d₁/t
t = d₁ / 2x
For car d;
x = d₂/t
t = d₂/ x
Since it takes both cars the same time to meet at the same point, therefore:
d₁/2x = d₂ / x
d₁ = 2d₂
d₁ - 2d₂ = 0 (2)
Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles
Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles
