Answer:
The correct answer is C
Step-by-step explanation:
Tbh I just guessed but I got a 100% on the test, so I hoped that helped
We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
Add 2 to both sdies
now if we can facor, then if
xy=0 then x and/or y=0
note:xy=x times y and x(y) =x times y
x^2+3x+2=0
what 2 number multiply to get 2 and add to get 3
the numbers are 2 and 1
(x+2)(x+1)=0
set them to zero
x+2=0
subtract 2
x=-2
x+1=0
subtract 1
x=-1
x could be -1 or -2
x=-2, or -1
Answer:
14
Step-by-step explanation:
Plug the 5 into the equation
2(5) + 4 = 14