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7nadin3 [17]
4 years ago
6

a marketing survey compiled data on the total number of televisions in households where k is a positie constant. What is the pro

bability that a randomly chosen household has at least two televisions?
Mathematics
1 answer:
MariettaO [177]4 years ago
3 0

Hi, you have not provided the distribution, I'll solve the problem for a particular distribution and you can apply the same method for yours.

Answer:

0.39

Step-by-step explanation:

X is the random event and P(X) is the probability of the event X, therefore, X is the number of  televisions

Distribution:

X        0         1         2        3       4         5

P(X)    0.24   0.37   0.20   0.11   0.05   0.03

When they ask for the probability of at least Two televisions, they are asking for the probability that the householder has two or more television or P(X>2). To calculate the probability we need to add the probability of each event in the range:

P(X>2) = P(2) + P(3) + P(4) + P(5) = 0.20 + 0.11 + 0.05 + 0.03 = 0.39

You might be interested in
A^2+2ab+b^2. solve for a=10 and b=50
qaws [65]
A² + 2ab + b² ; Solve when a=10 & b=50

Simply plug in 10 for a and 50 for b in our given equation :)

(10)² + 2(10)(50) + (50)²

Simplify.

100 + 20(50) + 2500

Simplify.

(100 + 2500) + 1000

Simplify.

2600 + 1000

Simplify.

3600

Hope I helped! :)

3 0
3 years ago
It's the 2nd question I know how it is done ....sum and product method but the root is confusing me can any one explain me plz
weeeeeb [17]
Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)

8 0
3 years ago
Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
3 years ago
I don’t understand what’s it asking me to do!! I have done this problem 12 times and I still don’t understand it. :(
pickupchik [31]
Solve for x. so first u would subtract 25 from 25 and 298. 25 will be crossed out so now u are left with 13x<273. to solve that, divide 13 on both sides. 13 would be crossed or so now u are left with x<13. that means x can equal anything less than 13. idk about the rest, i think u can do it. :)
4 0
3 years ago
Solve for x.
Trava [24]

Answer:

You said what now?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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