Answer:
Step-by-step explanation:
hello :
use pytagor-rule :
triangle ABC : (x+15)² =17²+y²....(*)
triangle BDC : y² = x²+8²....(**)
by (**) put the value of y² in (*) :
(x+15)² = 17²+x²+8²
x²+30x+15² = 17²+x²+18²
30x +225 = 289+64
30x = 128
x= 128/30
x= 64/15
put this value in (**) calculate y² ......continu
.
3x+5=0
3x=0-5
3x=-5
Divide both sides by 3
-1.6666.......
Hope it helps.
As for mod 9, I don't understand.
The answer is B. 4,7.5,8
Becouse A and C Both of them is Right-angled triangle and D is Obtuse triangle
dunno
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or ![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or ![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean