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3 years ago

8

What is the first step needed to solve 2 over 5 multiplied by x minus 6 equals negative 16 ? (1 point) Subtract 16 from both sid

es Add 6 to both sides Divide both sides by 5 Multiply both sides by 2

2 answers:

AfilCa [17]3 years ago

8 0

Answer:

The first step is Add 6 to both sides

Step-by-step explanation:

we have

$\frac{2}{5}x-6=-16$

Solve for x

That means ----> isolate the variable x

step 1

Adds 6 both sides

$\frac{2}{5}x-6+6=-16+6$

$\frac{2}{5}x=-10$

step 2

Multiply by 5/2 both sides

$\frac{2}{5}x(\frac{5}{2})=-10(\frac{5}{2})$

$x=-25$

therefore

The first step is Add 6 to both sides

defon3 years ago

3 0

I believe the answer for the first step would be add 6 to both sides

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alisha [4.7K]

$\\ \sf\longmapsto \dfrac{1}{3}x=18$

$\\ \sf\longmapsto \dfrac{x}{3}=18$

Use cross multiplication

$\\ \sf\longmapsto x=3(18)$

$\\ \sf\longmapsto x=54$

6 0

3 years ago

Read 2 more answers

Please solve with steps.

Kitty [74]

Answer: a) h = 2

b) a = $-\dfrac{3}{4}$ k = $\bold{3\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k where

a is the vertical stretch
(h, k) is the vertex

The graph shows the axis of symmetry at x = 2, therefore, the x-coordinate of the vertex (h) is 2.

Two points are given: $\bigg(0, \dfrac{1}{2}\bigg)\ and\ \bigg(3, 2 \dfrac{3}{4}\bigg)$ . We can use these points to create two equations and then solve the system to find the a and k-values.

y = a(x - 2)² + k

$\bigg(0, \dfrac{1}{2}\bigg)\\\rightarrow \dfrac{1}{2}=a(0-2)^2+k\\\\\rightarrow \dfrac{1}{2}=4a+k\\\\\rightarrow \dfrac{1}{2}-4a=k\\\\\\\bigg(3, 2\dfrac{3}{4}\bigg)\\\rightarrow 2\dfrac{3}{4}=a(3-2)^2+k\\\\\rightarrow 2\dfrac{3}{4}=a+k\\\\\rightarrow 2\dfrac{3}{4}-a=k\\\\\\\\\dfrac{1}{2}-4a=2\dfrac{3}{4}-a\\\\\dfrac{1}{2}-2\dfrac{3}{4}=4a-a\\\\\dfrac{2}{4}-\dfrac{11}{4}=3a\\\\-\dfrac{9}{4}=3a\\\\-\dfrac{9}{4\cdot 3}=\dfrac{3a}{3}\\\\ \bold{-\dfrac{3}{4}=a}$

Solve for k:

$2\dfrac{3}{4}-a=k\\\\\\2\dfrac{3}{4}-\bigg(-\dfrac{3}{4}\bigg)=k\\\\\\\bold{3\dfrac{1}{2}=k}$

5 0

3 years ago

The volume of a rectangular prism is 2,058 cm squared 3. The length of the prism is three times the width. The height is 14cm. F

Alborosie

Answer:

length is 21 cm

breadth is 7 cm

3 0

3 years ago

A quadrilateral has 2 pairs of congruent angles and 4 congruent sides. What is the name of the quadrilateral?

AfilCa [17]

Answer: Rhombus

A rhombus is a quadrilateral with all four sides the same length. If all four angles are the same (all 90 degrees), then the rhombus is more specifically a square. Any rhombus is a parallelogram which is why we have congruent opposite pairs of angles.

7 0

4 years ago

Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago