Answer:
c = 150 + 20b
Step-by-step explanation:
Given:
Ticket charges = $150
Each bag carry cost = $20
Find:
Relationship between bag(b) and cost(c)
Computation:
⇒ Total cost = Ticket charges + $20(number of bags)
⇒ c = 150 + 20(b)
⇒ c = 150 + 20b
The number of people increased by 2.
This means as a ratio it is now 6/4 as many as originally planned.
6/4 can be reduced to 3/2.
The time and the number of people are inversely proportional, so the food would last 2/3 ( inverse is flipping the original ratio over) the original length of time.
This means the length of time the food lasts is reduced by 1/3, which is 33.3%
I believe yes, no, no, no but I am not sure
The answer is around 10.22 mph
Answer:
The augmented matrix of the system is
.
We apply operations rows:
1. We swap row 1 and 2 and obtain the matrix
.
2. Of the above matrix we subtract row 1 from row 2 twice (R2 - 2R1) and we subtract row 1 from row 3, 5 times. (R3-5R1). We obtain the matrix ![\left[\begin{array}{cccc}1&2&1&4\\0&-1&-3&6\\0&-1&-3&-13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%261%264%5C%5C0%26-1%26-3%266%5C%5C0%26-1%26-3%26-13%5Cend%7Barray%7D%5Cright%5D)
3. Of the above matrix we subtract row 2 from row1 twice (R3 - R2) and multiply the row 1 by -1 (-R2). Weobtain the matrix
.
Since each pivote is an one then we conclude that the above matrix is the reduced row-echelon form of the matrix of the system.