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Wittaler [7]
3 years ago
5

Compare discrete domains and continuous domains.

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
Discrete domains and continuous domains are both sets. However a discrete domain contains a finite number of elements and continuous can contain and infinite number of elements.
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SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU <3
andrew11 [14]

Answer:

1. new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16

3. The new area is 1/9 of the original area.

Step-by-step explanation:

1. side length1 = x

side length2 = y

2x + 2y = perimeter

2(4x) + 2(4)y = new perimeter

8x + 8y = new perimeter

new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16. This is because the area formula has them being multiplied together and thus it will make the area go up by that much.

3. Let the length of the rectangle be x

Let width of rectangle be y

Area of rectangle =  L*W

Now Each side length of the rectangle is multiplied by 1/3

So, new area =  (1/3)L * (1/3)W

=(1/9)LW

So, the new area is 1/9 of the original area.

7 0
3 years ago
Does the data below describe a linear, quadratic, or exponential function?
laiz [17]

Answer:

Linear

Step-by-step explanation:

all values for y have a constant difference of -4.

That makes it linear due to a constant difference

6 0
3 years ago
Please help me i am desperate please (1/3)
Sergeu [11.5K]

I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?

I'll do the first page.

6)

Right triangle, opposite side of 10, adjacent side of 21,

tan x = opp/adj = 10/21

x = arctan 10/21 = 25.46°

Answer: 25

7)

cos x =   adj / hyp = 10/14

x = arccos 10/14 = 44.42°

Answer: 44

8)

tan x = opp/adj = 12/24 = 1/2

x = arctan 1/2 = 26.57°

Answer: 27

9)

tan x = 31/32

x = arctan 31/32 = 44.09°

Answer: 44

10)

x = arctan 10/27 = 20.32°

Answer: 20

8 0
3 years ago
The volume of a pyramid varies jointly as the height and the area of the base. If a pyramid has the measurements V=1144
Naddika [18.5K]

Answer:

  • 11040 m³
  • k ≈ 0.33
  • V = (1/3)Bh

Step-by-step explanation:

The given relation is ...

  V = kBh . . . . . for some base area B, height h, and constant of variation k

We are given length and width of the base so we presume it is a rectangle.

  B = l·w = 8·11 = 88 . . . . square meters

The given volume tells us the value of k:

  1144 = k(88)(39) . . . . . . cubic meters

  1144/3432 = k = 1/3 ≈ 0.33

The value of k is about 0.33.

__

Then the volume of the larger pyramid is ...

  V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³

The general relationship is ...

  V = 1/3Bh

7 0
3 years ago
May someone one hlrp
Marrrta [24]
52:)

explanation:

haha
5 0
3 years ago
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