Answer:
Both are correct.
Step-by-step explanation:
The key understanding here is that you can factor a monomial in many different ways!
To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x
7
12, x, start superscript, 7, end superscript.
Hint #22 / 4
\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}
(4x
3
)(3x
4
)
=(4)(3)(x
3
)(x
4
)
=12x
7
So Ibuki is correct!
Hint #33 / 4
\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}
(2x
6
)(6x)
=(2)(6)(x
6
)(x)
=12x
7
So Melodie is also correct!
Both Ibuki and Melodie are correct.
Answer:
Option A
Step-by-step explanation:
We can try to factorize all the options one by one.
For A:
![x^{2} +5x-4\\=> x^{2}+4x+x-4\\=>x(x+4)+1(x-4)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B5x-4%5C%5C%3D%3E%20x%5E%7B2%7D%2B4x%2Bx-4%5C%5C%3D%3Ex%28x%2B4%29%2B1%28x-4%29)
We can see that the quadratic expression cannot be solved by factorization as the factors at the end of factorization are not equal in both brackets. So Option A is the correct answer for the given question.
Moreover we can also note that all the other quadratic expressions can be factorized ..
STAN AND STREAM VICTON ATEEZ AND TXT NOW
Answer:
X=-6
Step-by-step explanation: