If the length of FH is 18 units, what is the value of x?

Mathematics

2 answers:

valentinak56 [21]2 years ago

5 0

Well if FG is 4x and GH is 2x the you add them to get 6x for FH. Solve for x so 6x=18 which means x=3. Hope this helps

Shkiper50 [21]2 years ago

5 0

we know that

$FH=FG+GH$

In this problem we have

$FH=18\ units\\FG=4x\\GH=2x$

substitute in the formula above

$18=4x+2x$

solve for x

$6x=18$

$x=18/6$

$x=3\ units$

therefore

<u>the answer is</u>

The value of x is $3\ units$

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2 years ago

The table below show 2 equations. Equation 1: 3x-1=7+2 Equation 2: 2x+1+4=3 which statement is true about the solution to the tw

olya-2409 [2.1K]

You have not added your options, so I will just solve and hope that my answer is in your choices.

For the first equation we have:
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For the second equation we have:
<span>2x+1+4=3
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Therefore, there isn't a solution that satisfies both equations. Based on this, this system of equations has no solution.

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Read 2 more answers

Select the correct answer from the drop-down menu. Find the product. The product of 2/5a2x and -1/5x2a is

valentinak56 [21]

Answer: $-\frac{2}{25}a^{3}x^{3}$

Step-by-step explanation:

1. The problem asked for the product of $\frac{2}{5}a^{2}x$ and $-\frac{1}{5}x^{2}a$ , therefore, you must mutliply them, as you can see below:

2. According the exponents propertiess, when you have a multiplication of two powers that has the equal base, you must add the exponents. THerefore, you have the following result:

$(\frac{2}{5}a^{2}x)(-\frac{1}{5}x^{2}a)=-\frac{2}{25}a^{3}x^{3}$