Whats your zodiac sign first to answer gets brailiest and 100 points

Dose Congruent Mean Having The Same Measure

Julli [10]

So Congruent. Two figures are congruent if they have the same shape and size. Two angles are congruent if they have the same measure. Two figures are similar if they have the same shape but not necessarily the same size.

I hope that help u:)

4 0

3 years ago

Una avenida está siendo asfaltada por etapas. En la primera etapa se asfaltó la mitad; en la segunda, la quinta parte, y en la t

s344n2d4d5 [400]

Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L

En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:

(2/40)*L = 200m

L = 200m*(40/2) = 4,000m

7 0

3 years ago

Find the number whose 12% is 725 students ? (Can someone answer this asap)

Tju [1.3M]

Answer:

6041.666.....

Step-by-step explanation:

We have: 725 : 12% = 6041.6666.....

4 0

2 years ago

Read 2 more answers

Someone help me lol..

disa [49]

Answer:

1/3x + 3 is the correct answer, hope it help

6 0

2 years ago

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$