We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if the building is expected to be 200 feet tall.

We will use proportions to solve our given problem as:

$\frac{\text{Model height}}{\text{Actual height}}=\frac{\text{Model length}}{\text{Actual length}}$

Upon substituting our given values, we will get:

$\frac{x}{200\text{ ft}}=\frac{3\text{ in}}{\text{32 ft}}$

$\frac{x}{200\text{ ft}}\times 200\text{ ft}=\frac{3\text{ in}}{\text{32 ft}}\times 200\text{ ft}$

$x=3\text{ in}\times 6.25$

$x=18.75\text{ in}$

Therefore, the model will be 18.75 inches tall.

7 0

3 years ago

If log_10(x) = 3 + log_10(y), then find x/y

Lina20 [59]

Answer:

1000

Step-by-step explanation:

$log_{10}x = 3 + log_{10}y$
$log_{10}x - log_{10}y = 3$
$log_{10}(x/y) = 3$
$x/y = 10^3$
$x/y = 1000$

7 0

2 years ago

Read 2 more answers