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zavuch27 [327]
4 years ago
14

Which answer shows these decimals written in order from greatest to least 23.697 23.72 22.8

Mathematics
2 answers:
9966 [12]4 years ago
6 0
Greatest to least

23.72, 23.697, 22.8

hope this helps

23.72 is greater than 23.697 by 0.023

Elza [17]4 years ago
5 0
The order from greatest to least is 23.72. Have a great day!
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Does anyone understand how to solve this?
Nataliya [291]

a f(a) is the function f(x) where x is replaced by a.

So we have

(3x^2 + x + 3 - (3a^2 + a + 3)) / ( x - a)

= (3x^2 - 3a^2 + x - a) / (x = a) Answer

b (3(x + h)^2 + x + h + 3 - (3x^2 + x + 3)) / h

= (3x^2 + 6xh + 3h^2 + x + h - 3x^2 - x - 3) ) / h

= (6xh + h + 3 h^2) / h

= 6x + 3h + 1 Answer



6 0
3 years ago
Solve the equation by the elimination method..!!
kramer

Step-by-step explanation:

given

3x + 4y = 10

as equation 1, and

2x - 2y = 2

as equation 2.

Now, multiply equation 2 by 2.

2x \times 2  - 2y \times 2 = 2 \times 2 \\ 4x - 4y = 4

now let's this equation be equation 3.

We now use equation 1 + equation 3 to eliminate y and find x.

3x + 4x  + 4y + ( - 4y) = 10 + 4 \\ 7x + 4y - 4y = 14 \\ 7x = 14 \\ x = 14 \div 2 \\  = 7

Now substitute x = 7 into equation 2.

2(7) - 2y = 2 \\ 14 - 2y = 2 \\  - 2y = 2 - 14 \\  - 2y =  - 12 \\ y =  - 12 \div  - 2 \\  = 6

4 0
3 years ago
Given f (x) = 3x – 5 and g(x) = 2x + 1, find g(f(x)). 6x2 – 7x – 5 6x – 10 6x – 2 6x – 9
N76 [4]

Answer:

g(f(x)) = 6x - 9

Step-by-step explanation:

To find g(f(x)), substitute x = f(x) into g(x) , that is

g(3x - 5)

= 2(3x - 5) + 1 ← distribute parenthesis and simplify

= 6x - 10 + 1

= 6x - 9

5 0
3 years ago
Read 2 more answers
Log5 (x squared - 9) = 0
andreev551 [17]

Answer:

x=3,\:x=-3

Step-by-step explanation:

Given the equation

\log _{10}\left(5\right)\left(x^2-9\right)=0

Divide both sides by \log _{10}\left(5\right)

\frac{\log _{10}\left(5\right)\left(x^2-9\right)}{\log _{10}\left(5\right)}=\frac{0}{\log _{10}\left(5\right)}

Simplify

x^2-9=0

Add 9 to both sides

x^2-9+9=0+9

Simplifying

x^2=9

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{9},\:x=-\sqrt{9}

as

\sqrt{9}\:=3

-\sqrt{9}=-3

Therefore,

x=3,\:x=-3

3 0
3 years ago
What are the amplitude, period, and midline of f(x) = 3 cos(4x − π) + 2?
Fudgin [204]
<span>Amplitude: 3; period: pi/2; midline: y = 2</span>
7 0
3 years ago
Read 2 more answers
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