10/1 * 1/3 = 30/3
1 1/3 = 4/3
4/3 can only go into 30/3, 7 times, with a remainder of 2/3.
7 2/3
Answer:
218
Step-by-step explanation:
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Answer:
AC=15
BC=17
AB=?
According to Pythagore's Theorem: AB² + AC² = BC².
AB² = BC² - AC²
= (17)² - (15)²
= 289 - 225
AB² = 64
AB = √(64)
= 8.
So AB = 8.
We keep the 2x^2 because we can only subtract something from that if it also is squared. From there, we subtract the 7x from 2x^2-11. Since there is no previous x's in the 2x^2-11, we just make it -7x. So, without even continuing the problem, we see that A) is the correct answer because it is the only one with -7x.