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Zolol [24]
3 years ago
15

Expanded fraction 876,543,210.25

Mathematics
2 answers:
Kipish [7]3 years ago
6 0
800,000,000.00
70,000,000.00
6,000,000.00
500,000.00
40,000.00
3,000.00
200.00
10.00
0.00
0.20
0.05
Nesterboy [21]3 years ago
6 0
80000000000+ 7000000000+600000000+50000000+4000000+300000+20000+1000+ 20+ 5
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6^2+17+12 help me plz.
Dmitry_Shevchenko [17]
6^2 + 17 + 12

First, let's start with 6^{2} . Basically, the '2' above the 6 indicates that the number appears twice in multiplying. 6^{2} can be described as 6 × 6 as well. 36 should be your answer for 6 squared.
6^{2} = 6 \times 6 = 36

Second, our problem should look like: 36 + 17 + 12. One can simply do this on a calculator or count on their fingers. Once you add all of the numbers up, you should get 65.

Answer: \fbox {65}
4 0
3 years ago
Read 2 more answers
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
use the substitution method to solve the system of equations. Choose the correct ordered pair. y=4x 8x+y=18
tino4ka555 [31]

Answer:

(3/2, 6)

Step-by-step explanation:

y = 4x

8x + y = 18

this says y is 4x so you can replace y with 4x

8x + 4x = 18

12x = 18

/12      /12

  x  = 3/2


now sub x into y = 4(3/2)

y = 12/2

y = 6

8 0
4 years ago
Read 2 more answers
If natalie and her friends decide to rent 4 lanes at reguler cost for a party ten people need to rent shoes and 4 people are mem
taurus [48]

The question is missing a tabular data. So, it is attached below.

Answer:

The total cost for the party is $74.50.

Step-by-step explanation:

Given:

Lanes rented at regular cost = 4

Cost of 1 lane rented  at regular cost = $9.75

Cost of 1 lane rented for members = $7.50

Cost of 1 shoe rental at regular cost(non members) = $3.95

Cost of 1 shoe rental for members = $2.95

Since, lanes are rented at regular cost, we use unit rate at regular cost

So, cost of 4 lanes rented = 4\times 9.75= \$ 39

Now, out of 10 people who rented shoes, 4 are members. So, the number of non-members is given as:

Non members who rented shoes = 10 - 4 = 6

So, 4 members and 6 nonmembers rented shoes.

So, cost of 6 non members renting shoes = 6\times 3.95=\$ 23.70

Cost of 4 members renting shoes = 4\times 2.95=\$ 11.80

Total cost for the party is the sum of all the costs. This gives,

= 39 + 11.80 + 23.70

= 50.80 + 23.70

= $74.50

Therefore, the total cost for the party is $74.50.

5 0
3 years ago
6th grade math help me pleaseeee
Mrac [35]
Again lol. and they were the same age at 3 weeks.
3 0
3 years ago
Read 2 more answers
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