Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in form
where where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get
r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.
When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
Answer:
I don't have an image to show you, but I can explain where to put it
Step-by-step explanation:
A) Draw PQR Upside down, but in the top right corner.
B) Draw PQR in the bottom right corner.
It's a bit confusing, but it's the best I can do, ask questions if you need more explanation please :)
I think 16 is a right angle? i can’t really see the picture can you post a better picture for the images
Answer:
Well you could get use g o o g l e s calculator or write it out.
Step-by-step explanation:
Its 5y sorry if it’s wrong