Question

A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is the cyclist’s initial velocity?

Answer 1

Change in velocity ($\Delta v$) is acceleration ($a$) times time ($t$)

Acceleration $a=1.2\ m/s^{2}$
Time $t=10\ s$
So $\Delta v=at=1.2\ m/s^{2}*10\ s=12\ m/s$

The initial velocity is then $16\ m/s-12\ m/s=4\ m/s$

Answer 2

the answer to the problem is 4m/s