Invasive species or environment
The right option is; b. anticipatory socialization.
Playing house as a child is a form of anticipatory socialization.
Anticipatory socialization is the process in which an individual changes his behaviors or learn new norms and values in preparation for a change in his role in the future. Playing house which is children’s game is a form of anticipatory socialization because when children play the game, they take the roles of a nuclear family such as children, parents, and newborns. Due to children’s experience with the game, they are prepared for adulthood.
Proper nutrition promotes growth, leads to health and longevity, and promotes intellectual growth by affecting the brain and psyche.
Nature in general refers to the phenomenon of the physical world as well as life; It also extends from subatomic particles to the universe itself.
Answer:

Explanation:
The <em>vapor pressure lowering</em> is a colligative property and it follows Raoult's law.
The <em>vapor pressure lowering</em> of a solvent in a solution, ΔP, is equal to the mole fraction of the solute, Xsolute, multiplied by the vapor pressure of the pure solvent, P°.

ΔP and P⁰ are given:
<u>1. Mole fraction of solute</u>
Thus, you can calculate Xsolute:

<u>2. Moles of solute</u>
Now you can calculate the number of moles of water and the number of moles of solute.
- Number of moles of water = mass in grams / molar mass
- Number of moles of water = 1,250g/18.015 (g/mol) = 69.3866mol
- Xsolvent = 1 - Xsolute = 1 - 0.02513 = 0.97487
- Xsolvent = moles of solvent / moles of solution
- 0.97487 = 69.3866mol / moles of solution
- moles of solution = 71.1752mol
- moles of solute = moles of solution - moles of solvent = 71.1752mol - 69.3866mol = 1.7886mol
<u>3. Mass of urea</u>
Formula:
- Mass = number of moles × molar mass
- Mass = 1.7886 mol × 60.06 g/mol = 107.42 g
You must round to 3 significant figures: 107 g