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sukhopar [10]
3 years ago
7

A problem that you will encounter in calculus 2 is finding the area under a curve. for the function f(x=-2x2-5x+3

Mathematics
1 answer:
serg [7]3 years ago
5 0
x-intercepts occur at points (x_i,0), so it follows that setting f(x)=0 and solving for x will give you the x-coordinate of an intercept.

-2x^2-5x+3=0\iff-(2x-1)(x+3)=0\implies x=\dfrac12,x=-3

So the two intercepts are (-3,0) and \left(\dfrac12,0\right). For values of x between the two intercepts, say at x=0, you have f(0)=3>0, which means the bounded region lies above the x-axis.

The area of the bounded region is then given explicitly by the definite integral

\displaystyle\int_{-3}^{1/2}f(x)\,\mathrm dx

Barring that (given your "no calc explanations allowed" caveat), the best you can do is to approximate the area of the region with basic shapes.
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D.

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8 0
4 years ago
A business bought a lot of 2,500 lamps for 50,000 dollars and wants to sell them at 15 percent profit how much should each lamp
aev [14]
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I should just shut up now...answer is $ 23 per lamp


4 0
4 years ago
Given: m∠A = m∠C = 90°<br> AB ║ DC<br> Prove: ∆ABD ≅ ∆CDB<br> 40 points
leonid [27]

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angle a and c are right angles so they are equal and angle b and d are equal because they have a line that touch both letters

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3 years ago
PQRS is a rectangle.
Anuta_ua [19.1K]

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diagram pls

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At your job, you are paid $50 per week plus $3 per sale. At least how many sales do you need to make in order to have over $250
julsineya [31]

<span>0+3⋅c>250</span>

<span>50+3⋅c−50>250−50</span>

<span>3⋅c>200</span>

<span><span><span>3⋅c</span>3</span>><span>2003</span></span>

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4 years ago
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