C is the answer because there are a lot of trees in the rainforest
A person whose red blood cells agglutinate with anti-B antibodies BUT NOT anti-A antibodies is type AB.
<h3>What is an agglutinate?</h3>
Agglutination is the process by which specific antibodies to antigenic components on the surface of red blood cells or inert particles (direct agglutination) or to antigenic components adsorbed or chemically attached to red blood cells or inert particles produce clumps of cells or inert particles (passive hemagglutination and passive agglutination, respectively).
When antibodies on one RBC attach to the antigen on another RBC, a process known as agglutination, globular to amorphous, grape-like aggregates of RBCs are formed. RBC agglutination supports immune-mediated hemolytic anemia when it is present (IMHA). The majority of IMHA instances do not exhibit agglutination, but when it does, immunoglobulin M (IgM) is the most frequently implicated because of its pentavalent nature. Agglutination, however, might be brought on by a very thick IgG antibody coating of the RBC membranes. Agglutination is typically regarded as IMHA's diagnostic sign.
Learn more about Agglutination here:
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The nurse should first select an area to perform the hyphodermoclysis, outside of the elbow is usual but the back of the hand is fine too. Then the nurse must apply a tourniquet 10 cm before the selected area, so it blocks blood circulation. After feeling the vein stand out in the selected area, said area must be cleaned with an antiseptic solution. Then the nurse should introduce the needle connected to the catheter in the outstanding vein, following along the anatomy of the patient against the normal bloodstream direction, so the needle stays almost parallel to the vein while inserted. Finally the nurse must fix the needle to the arm using medical adhesive, and remove the tourniquet.
Answer:
Q(0) = 0C, Q(1) = 264nC, Q(2) = 952C Q(3) = 2088nC, Q(4) = 3696C Q(5) = 5800nC
Explanation:
I = 4t³ + 200t² + 60t
But charge of an object =》 Q = IT
Charge of an object is the product of the current and the time in which the current passes through the membrane.
When t = 0
Q = 4(0)³ + 200(0)² + 60(0) = 0C
When t = 1
Q = 4(1)³ + 200(1)² + 60(1) = 264nC
When t = 2
Q = 4(2)³ + 200(2)² + 60(2) = 952nC
When t= 3
Q = 4(3)³ + 200(3)² + 60(3) = 2088nC
When t= 4
Q = 4(4)³ + 200(4)² + 60(4) = 3696nC
When t = 5
Q = 4(5)³ + 200(5)² + 60(5) = 5800nC
