Answer:
(0,-1),(1,0),(2,1),(3,2)
Step-by-step explanation:
We are given that a relation
y=x+1y=x+1
We have to find the four points contained in the inverse
The given function is linear function
Therefore,
Domain of function=R
Range of function=R
x=y-1x=y−1
Now, replace x by y and y replace by x
y=x-1y=x−1
Now, substitute y=f^{-1}(x)=f
−1
(x)
f^{-1}(x)=x-1f
−1
(x)=x−1
It is linear function and defined for all real values.
Substitute x=0
f^{-1}(0)=-1f
−1
(0)=−1
Substitute x=1
f^{-1}(1)=1-1=0f
−1
(1)=1−1=0
f^{-1}(2)=2-1=1f
−1
(2)=2−1=1
f^{-1}(3)=3-1=2f
−1
(3)=3−1=2
Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)
Step-by-step explanation:
Answer:
81
Step-by-step explanation:
Answer: x=1 or x=-3
Step-by-step explanation:
Quadratic formula is 
a=1 b=2 c=-3
Substitute
|2x-3|=2x-1
need to consider two cases
(1) 2x-3<0 --> x<3/2
-(2x-3)=2x-1
x=1, and this is <3/2 so that's a valid solution
(2) 2x-3>=0 --> x>=3/2
2x-3=2x-1
-3 = -1 so there no solution for x>=3/2
The single solution is x=-1
