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Fynjy0 [20]
3 years ago
15

I need help with this answer i have been stuck

Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

13.

Step-by-step explanation: divide 15 and 10 to get 1.5 and then multiply 1.5 by 9


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Can someone help me please
soldier1979 [14.2K]

Step-by-step explanation:

c >= 2

that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.

c < 2

that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.

c < 3

that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.

3 < c

that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.

-8 < c

that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.

5 0
2 years ago
Three consecutive whole numbers are such that if they be divided by 5,3 and 4 respectively, the sum of the quotient is 40. What
Alja [10]
\dfrac{x}{5}+\dfrac{x+1}{3}+\dfrac{x+2}{4}=40\\&#10;12x+20(x+1)+15(x+2)=2400\\&#10;12x+20x+20+15x+30=2400\\&#10;47x=2350\\&#10;x=50\\&#10;x+1=51\\&#10;x+2=52

Then umbers are 50,51,52
4 0
3 years ago
Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.
aleksandrvk [35]

Answer:

The value of x is 3/2.

Step-by-step explanation:

Given data in the question:-

3^2^x=27

We have to find the value x.

Let 3^2^x=27 be eq(i).

Solving eq (i)

3^2^x=3^3

using the properties of the exponents we have

if aⁿ=aˣ

then n=x

2x=3\\x=3/2

Hence the answer is 3/2.

4 0
3 years ago
(04.02 MC) Are the following figures similar? ​
Kitty [74]

Answer:

B correct me if i am wrong!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write an exponential equation in the form y = ab* whose graph passes through points (2, 18) and (5, 60.75).
DochEvi [55]

Let y=ab^x, as described in the problem statement. Plugging in x=2 and x=5 gives us the equations 18=ab^2 and 60.75=ab^5. Since a,b are nonzero, we divide the second equation by the first to get \frac{27}{8}=b^3, which means that b=\frac{3}{2}, after taking the cube root. Plugging this value for b into the first equation, we now have 18=a(3/2)^2=\frac{9a}{4}. Solving gives a=8, and our desired exponential equation is \boxed{y=8\left(\frac{3}{2}\right)^x}.

8 0
3 years ago
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