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scoundrel [369]
4 years ago
6

A rectangular television's length is 3 inches more than twice its width. The perimeter of the television is 144 inches. What is

the width of the television?
A. 23
B. 24
C. 25
D. 26
can someone explain bc I got small brain ykyk
Mathematics
1 answer:
e-lub [12.9K]4 years ago
8 0

Answer: <u><em>A. 23</em></u>

23 - <em>Width</em>

23x2 = 46

46+3 = 49

So..

49 - <em>Length</em>

lx2+wx2 = <em>perimeter</em>

<em>49x2 = 98</em>

<em>23x2 = 46</em>

<em>98+46 = 144</em>

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F(x)= 1/x; Find f (0.01)​
ohaa [14]

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Given the definitions of f(x) and g(x) below, find the value of (g o f)(0).
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3 years ago
Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

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framing in equation form, we get;

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Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

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Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

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Hence Length of the sandbox is 10 feet.

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