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2 years ago

Given the definitions of f(x) and g(x) below, find the value of (g o f)(0).

Mathematics

1 answer:

Mamont248 [21]2 years ago

7 0

Answer:

its 3

so its

(4x+4)^2-2(4x+4)-5

so first you have to do

(4x+4)(4x+4)

the answer is 16x^2+32x+16

and then you do -2(4x+4) and then you add them so then its

16x^2+32x+16-8x-8-5

and then you just add like terms so its

16x^2+24x+3

and then you insert 0 for x

so the answer is 3

Step-by-step explanation:

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Evaluate the expression if a = 2, b = −3, c = −4, h = 6, y = 4, and z = −1.

scZoUnD [109]

Step-by-step explanation:

Hope it helps. Please mark as brainliest.

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2 years ago

Shawna, Dexter, and Tilana are solving the equation -2.5(5-n)+2=15. Shawna says, “I can begin by dividing each side of the equat

laila [671]

Hi!
Shawna is correct because since it's multiplied to the 5-n you have to do the opposite which is division.
Dexter is also correct because after distributing you can continue solving, there is nothing wrong with that.
Hope this helps!

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2 years ago

Read 2 more answers

PLEASE DON’T ANSWER IF YOU DONT KNOW THE ANSWER!!!

Blababa [14]

D should be correct because you add all the boxes that’s inside the rectangle

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2 years ago

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Creative landscaping has 60 yards of fencing with which to enclose a rectangular flower garden. If the garden is X yards long, e

7nadin3 [17]

Answer:

$\texttt{Area = Length x Width}\\\\\texttt{Area =}x\times (30-x)=30x-x^2\\\\\texttt{Area =}30x-x^2$

<h3>Area, A(x) = 30x - x² , as a function of the length (x).</h3>

Step-by-step explanation:

Creative Landscaping has 60 yard of fencing with which to enclose a rectangular garden.

If the garden is X yards long, express the Gardens area as a function of length

Let x be the length of garden

So perimeter of rectangle = 60 yard

Perimeter = 2 * ( Length + width)

60 = 2 * ( x + width)

Width = 60/2 - x

Width= 30 - x

$\texttt{Area = Length x Width}\\\\\texttt{Area =}x\times (30-x)=30x-x^2\\\\\texttt{Area =}30x-x^2$

<h3>Area, A(x) = 30x - x² , as a function of the length (x).</h3>

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3 years ago

What are the six trigonometric functions of theta = 2pi ?

mafiozo [28]

sinx=sin(π3−π)=−sin(π3)=−12.
cosx=cos(π3−π)=−cos(π3)=−√32.
tanx=−12−√32=1√3=√3.
cotx=1√3=√33.
secx=1cos=−2√3=−2√33.
cscx=1sin=−2.

3 0

2 years ago