20\2=10
10\2=5
5\2=2.5
2.5\2=1.25
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
38 students
Step-by-step explanation:
251 students minus the students traveled in cars =228 divide that by six buses and your outcome will be 38 students
Let's do this step by step:
Subtract both sides by 7
-2|x-4|= -10
Divide each side by -2
|x-4|= 5
Now since this is an absolute value equation, you will have two answers. This means you make the equation both positive and negative.
X-4= 5and -(x-4)= 5
Solve for x for both
X-4= 5: add four on both sides
X= 9
-x+ 4= 5: subtract 4 and divide by -1
X= -1
So your answer is: X= -1 , 9
