ALGEBRA 2 HELP PLEASE

Find the slope of the line containing points (1,3) (-3,-8)

Y=mx+c
1/-3=m3/8+c
m= 11/4

4 0

3 years ago

A company paid $72 for 2 cases of printer paper each case contained 12 packages of paper next month the company's office manager

Tems11 [23]

To figure out the cost for 180 packages, you must first calculate how many packages they bought for $72. Since each case holds 12 packages, for $72, the company bought 24 packages (12×2). Then you have to divide 24 into 180 to figure out the cost for those 180 packages and get 7.5. To get the cost of the 180 packages, you must multiply 7.5 (the number of 24 packages that go into 180) by 72 (the cost of one group of 24 packages). You then get 540. The company must pay $540 for the 180 packages.

7 0

3 years ago

For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl

nevsk [136]

I'm assuming you're talking about the indefinite integral

$\displaystyle\int e^{-x^2/2}\,\mathrm dx$

and that your question is whether the substitution $u=\dfrac x{\sqrt2}$ would work. Well, let's check it out:

$u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}$
$\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du$
$=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du$

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried $u=\sqrt t$ next? Then $\mathrm du=\dfrac{\mathrm dt}{2\sqrt t}$ , giving

$=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt$

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

$\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt$

By the fundamental theorem of calculus, taking the derivative of both sides yields

$\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}$

and so the antiderivative would be

$\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)$

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.

3 0

3 years ago

The Math Club is raising money so they can attend a local competition next month. They have already raised $125 and they are sel

prisoha [69]

Answer: 100 candy bars

Step-by-step explanation:

You did not include the question but judging by the progression I can assume that the question is along the lines of how many candy bars they will need to sell to reach their target.

You did not include the amount they have to raise as well so let us assume that number is $375.

Assuming they have to raise $375 and they have already raised $125, the amount left to be raised is:

= 375 - 125

= $250

With each candy bar selling at $2.50, the number of candy bars they will need to sell is:

= 250/ 2.50

= 100 candy bars

<em>You should use this process to find the answer to your question. </em>

3 0

3 years ago

1/7+2/3= plz help ive been stuck on the question

Romashka [77]

Answer:

1/7+2/3

3+14/21

17/21

3 0

3 years ago

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ALGEBRA 2 HELP PLEASE ​

ALGEBRA 2 HELP PLEASE