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Greeley [361]
2 years ago
5

Help

Mathematics
1 answer:
weeeeeb [17]2 years ago
3 0

Answer:

If a polygon is convex, then the sum of the measures of the exterior angles, one at each vertex, is 360° .

Consider the sum of the measures of the exterior angles for an n -gon.

N=180n−180(n−2)

Distribute 180 .

N=180n−180n+360 =360.

Step-by-step explanation:

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Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5. A) −93. B) −33. C) 33. D) 93
lions [1.4K]
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
4 0
3 years ago
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I need some serious help rn, i got stuck
nordsb [41]

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

7 0
2 years ago
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Help i need help with this problem
Cloud [144]

Answer:

<em>Natalie's total spread = 18</em>

Step-by-step explanation:

The 'spread' of a crossword puzzle tournament player is computed as his/her total score minus the opponent's total score.

Natalie's scores are:

N=410+380+395+370+320+360=2,235

Opponent's scores are:

O=395+360+412+355+340+355=2,217

Natalie's total spread = 2,235 - 2,217 = +18

Natalie's total spread = 18

4 0
3 years ago
An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length
zvonat [6]

The two ways to find the ratio of the length is to turn the inches into feet or the feet into inches

So the answer can be solved like this:

1/36ft to 1/4ft which is 9:1 (blueprint size to actual size)

or

1/3in to 3in which is also 9:1 (blueprint size to actual size)

3 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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