Question

Anitas a fast food chain specialising in hot dogs and garlic fries, keeps track of the proportion of its customers who decide to eat in the restaurant (as opposed to ordering food to go) so it can make decisions regarding the possible construction of in- store play areas the attendance of its mascot Sammy at the franchise locations, and soon. Aitas reports that 45% of its customers order their food to go. If this proportion is correct what is the probability that, in a random sample of 4 customers at Anitas exactly 3 order their foodto go?
Round your response to at least three decimal places

Answer 1

The probability that one customer will place a take-out order is .45.
The probability that one customer will place an "eat in" order is .55.

Of 4 randomly selected customers, the probability that exactly 3 will order "take out" is given by the following:
$C^4_3\times 0.45^3\times0.55^1\approx0.200475$