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den301095 [7]
3 years ago
5

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term

s of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, –3, 2, 5, –4, –6 ? One
Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer: the number of variations in sign = 3

Step-by-step explanation:

Let the finite sequence 1, –3, 2, 5, –4, –6 , the only pairs of consecutive terms for which the product of the two consecutive terms is negative are :

{1, –3} ; {–3, 2}; {5, –4} then

the number of variations in sign = 3

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Two friends are collecting cards. Frank has 7 more than half the number of cards as his friend. Together they have 42 cards. How
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Answer:

The number of cards Frank has is 18 and the number of cards his friend has is 24.

Step-by-step explanation:

<u><em>The correct question is </em></u>

Two friends are collecting cards. Frank has 6 more than half the number of cards as his friend. Together they have 42 cards. How many cards does each friend have?

Let

x ----> the number of cards that Frank has

y ----> the number of cards that his friend has

we know that

Together they have 42 cards

x+y=42 ----> equation A

Frank has 6 more than half the number of cards as his friend

x=\frac{y}{2} +6 ---> equation B

Solve the system by substitution    

Substitute equation B in equation A

\frac{y}{2} +6+y=42

solve for y

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<em>Find the value of x</em>

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