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den301095 [7]
3 years ago
5

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term

s of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, –3, 2, 5, –4, –6 ? One
Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer: the number of variations in sign = 3

Step-by-step explanation:

Let the finite sequence 1, –3, 2, 5, –4, –6 , the only pairs of consecutive terms for which the product of the two consecutive terms is negative are :

{1, –3} ; {–3, 2}; {5, –4} then

the number of variations in sign = 3

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