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forsale [732]
3 years ago
11

I need to write this 1/2 as a decimal and a fraction

Mathematics
2 answers:
kompoz [17]3 years ago
5 0
1/2 as a decimal would be 0.5
1/2 as a fraction is 1/2<span />
tankabanditka [31]3 years ago
3 0
Hopefully I'm interpreting what your question is correctly, but here is my view.
To get your decimal you would simply divide 1 by 2 to get 0.5
To get your fraction, it is already in fraction form. 1/2 cannot be reduced any further.

Hope I read your question correctly and I hope I helped you out!
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With an x intercept of 5 and a y intercept of -5
stealth61 [152]

Answer:

-25

Step-by-step explanation:

8 0
3 years ago
Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′.
Goryan [66]
M` = ( 0.8 * 2,  0.8 *4 ) = 0.8 * ( 2, 4 );
N` = ( 0.8 * 3, 0.8 * 5 ) = 0.8 * ( 3 , 5 ).  
The slope of line M`N` ( after dilation ):
m = Rise / Run = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= 0.8 * ( 5 - 4 ) / ( 0.8 ( 3 - 2 ) = 0.8 / 0.8 = 1
m = 1
Answer:
The slope of line M`N` is : B ) 1
4 0
3 years ago
Solve the system of equations by elimintion express the solution as and order paired
tester [92]
First convert the first equation to combine like terms. Then set your equations up as an addition problem. You want at least one of your variables (y) to be of opposite values so the will cancel out to leave you with just one variable (x). Plug in 1/3 for the x into one of the equations to solve for y. Then write as an ordered pair.

3 0
2 years ago
F $1 \le a \le 10$ and $1 \le b \le 36$, for how many ordered pairs of integers $(a, b)$ is $\sqrt{a + \sqrt{b}}$ an integer?
svetlana [45]
You have such entry data: 
1\ \textless \ a\ \textless \ 10 \\ 1\ \textless \ b\ \textless \ 36

Consider expression \sqrt{a+ \sqrt{b} }. If this expression becomes an integer, then b=4,9,16,25, because then \sqrt{b} = 2,3,4,5, respectively. In other cases \sqrt{b} is not integer and thus the expression \sqrt{a+ \sqrt{b} } also is not integer.

1. b=4, then \sqrt{a+ \sqrt{b} }=\sqrt{a+2}. Here a=2,7 (in other cases \sqrt{a+2} is not integer). When a=2, \sqrt{a+2}=\sqrt{2+2}=2 and when a=7, \sqrt{a+2}=\sqrt{7+2}=3.

2. b=9, then a=6 and \sqrt{a+ \sqrt{b} }= \sqrt{a+3}=\sqrt{6+3}=3.

3. b=16, then a=5 and \sqrt{a+ \sqrt{b} }= \sqrt{a+4}=\sqrt{5+4}=3.

4. b=25, then a=4 and \sqrt{a+ \sqrt{b} }=\sqrt{a+5}=\sqrt{4+5}=3.

Answer: (2,4), (7,4), (6,9), (5,16), (4,25).







3 0
3 years ago
Help me for 50 points​
Sergeeva-Olga [200]

Answer:

I hope it helped U

stay safe stay happy

7 0
3 years ago
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