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Anika [276]
3 years ago
15

Please help asap!!!!!!!!!!

Mathematics
1 answer:
elena-s [515]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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Jack has two jars of wax. One jar is 1/6 full. The other jar is 4/6 full. Write an equation to find the amount of wax Jack has.
Solnce55 [7]

Answer:

1/6 + 4/6 = 5/6

Step-by-step explanation:

I hope this helped

5 0
3 years ago
5-2(3z+2)=-4(1-2z) please help lol
Sveta_85 [38]

Answer:

z= 5/14

Step-by-step explanation:

Let's solve your equation step-by-step.

5−2(3z+2)=−4(1−2z)

Step 1: Simplify both sides of the equation.

5−2(3z+2)=−4(1−2z)

5+(−2)(3z)+(−2)(2)=(−4)(1)+(−4)(−2z)(Distribute)

5+−6z+−4=−4+8z

(−6z)+(5+−4)=8z−4(Combine Like Terms)

−6z+1=8z−4

−6z+1=8z−4

Step 2: Subtract 8z from both sides.

−6z+1−8z=8z−4−8z

−14z+1=−4

Step 3: Subtract 1 from both sides.

−14z+1−1=−4−1

−14z=−5

Step 4: Divide both sides by -14.

−14z/ = -5

−14      -14

=5/14

z= 5/14

3 0
3 years ago
you consistently deposit 250.00 into a savings account on the 15th of each month, and the amount earns a 2.5 APR How much is the
frosja888 [35]

Answer:

Balance of savings account at the end of 3rd month = $753.13

Step-by-step explanation:

Balance at the end of 1st month :

Principal = $250 , Time = 1 month , n = 12 , APR = 2.5%

\text{Compound Interest = }Principal\times (1+\frac{rate}{n\times 100})^{n\times Time}\\\\=250\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$250.52

Balance at the end of second month :

Principal = 250 + 250.52

              = 500.52

Time = 1 month, APR = 2.5%, n = 12

\text{Compound Interest = }500.52\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$501.56

Balance at the end of third month :

Principal = 250 + 501.56

              = 751.56

Time = 1 month, APR = 2.5%, n = 12

\text{Compound Interest = }751.56\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$753.13

Hence, Balance of savings account at the end of 3rd month = $753.13

6 0
3 years ago
A scientist dropped an object from a height of 200 feet. She recorded the height of the object in 0.5-second intervals. Her data
Reil [10]
The quadratic model is given by:
 y = ax2 + bx + c
 We evaluate three points to find the values of a, b and c.
 We have then:
 For (0, 200):
 200 = a (0) 2 + b (0) + c
 c = 200
 For (0.5, 195):
 195 = a * (0.5) ^ 2 + b * (0.5) +200
 195-200 = a * (0.5) ^ 2 + b * (0.5)
 -5 = 0.25a + 0.5b
 For (1, 185):
 185 = a * (1) ^ 2 + b * (1) +200
 185-200 = a * (1) ^ 2 + b * (1)
 -15 = a + b
 Solving the system:
 -5 = 0.25a + 0.5b
 -15 = a + b
 We have the following results:
 a = -10
 b = -5
 Substituting:
 y = -10x ^ 2 - 5x + 200
 For x = 3 we have:
 y = -10 (3) ^ 2 - 5 (3) + 200
 y = - 90 - 15 + 200
 y = 95
 Answer:
 
the height at 3 seconds is:
 
y = 95 feet
3 0
3 years ago
On a vertical number line,where are the negative number plotted
attashe74 [19]

Answer:

The lower half

Step-by-step explanation:

5 0
3 years ago
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