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2 years ago

Help i need help i can't figure this out

Mathematics

2 answers:

EastWind [94]2 years ago

7 0

Answer: A) 23

Step-by-step explanation:

3^2 + ( 6 - 2 ) ⋅ 4 -6/3

3^2 + 4 ⋅ 4 -6/3

9 + 4 ⋅ 4 -6/3

9 + 16 -6/3

25 - 6/3

75/3 -6/3 = 69/3

69/3 = 23

lbvjy [14]2 years ago

5 0

Answer:

Step-by-step explanation:

3^2 + (6 - 2) x 4 - 6/3

3^2 + 4 x 4 - 6/3

9 + 16 - 6/3

25 - 6/3

6/3 = 2

25 - 2 = 23

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Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

7 0

3 years ago

How do i solve (4+6i)+(8-10i)?

ELEN [110]

Answer:

12- 4i

Step-by-step explanation:

(4+6i)+(8-10i)

4+6i+8-10i

4+8+6i-10i

12-4i

6 0

2 years ago

In 79 CE, a volcano erupted near Pompeii. Within a day, the city was buried under nine feet of ash. How many inches of ash burie

larisa86 [58]

You just do 12 * 9 and get 108 inches

3 0

2 years ago

What’s the correct answer for this question?

Ad libitum [116K]

Answer:

Step-by-step explanation:

Both angles add up to 180°

<BCG + <BFG = 180°

2x+146+4x+238=180

6x+384 = 180°

6x = 180-384

6x = -204

Dividing both sides by 6

x = -34

8 0

3 years ago

Prove sin^2 theta-sin^2 theta is sin tetha sin 3 theta how to prove..pls help!! thanksss

Artemon [7]

Simply you can substitute theta=45 degrees (or any angle,not zero) in left hand side and right hand side.

or

using a^2 - b^2 =(a+b)(a-b)

= sin(2x+x)sin(2x-x)
= sin 3x sin x

3 0

2 years ago

Help i need help i can't figure this out​

Help i need help i can't figure this out