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dolphi86 [110]
3 years ago
15

Please help

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

D

Step-by-step explanation:

given

V = \frac{1}{3} bh

multiply both sides by 3 to eliminate the fraction

3V = bh ( divide both sides by h )

b = \frac{3V}{h} → D


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If B=3x-1 and C=2x^2+x+9, find an expression that equals 2B+2C in standard form.
Anestetic [448]

Answer:

4x^2 +8x + 16

Step-by-step explanation:

2 (3x - 1) + 2 (2x^2 + x + 9)

6x - 2 + 4x^2 +2x + 18

4x^2 + 8x +16

3 0
3 years ago
What is the change of rate for the set of ordered pairs??
Alecsey [184]

Answer:

1/3 I think

Step-by-step explanation:

3 0
3 years ago
Dean needs 60 inches of wood to build a rectangular picture frame. The length l of the frame is twice its width w. Three of thes
damaskus [11]
Equation D does not give the correct value of w because P= 2W + 2L. If needed I can explain more in depth.
4 0
3 years ago
Read 2 more answers
A null hypothesis is being tested. How does the confidence level affect the testing process?
never [62]
The confidence level C and the significance level alpha are linked through the equation

alpha = 1-C

So for instance, if the confidence level is C = 95% = 0.95 then alpha is 

alpha = 1-C
alpha = 1-0.95
alpha = 0.05

meaning we have a 5% significance level. The larger C gets, the smaller alpha gets and vice versa. It turns out that 0 < C < 1 and also 0 < alpha < 1. 

The closer C gets to 1, the alpha value gets closer to 0. The smaller alpha gets, the harder it is to reject the null. Why is that? If we have a fixed p value, say p = 0.02 then we reject the null if alpha > pvalue. But we fail to reject the null when alpha < pvalue. For very small alpha values, we're going to fail to reject H0 no matter how small the pvalue is. The pvalue would have to be really small for H0 to be rejected.

In short, I'm saying that if the confidence level is high, then the chance of rejecting the null hypothesis is low (or rare)

This is why the answer is choice A
4 0
3 years ago
Alex and Leandro purchase two matinee movie tickets . A matinee ticket costs $6.50, a drink costs $5.50,and a bag of popcorn cos
xxTIMURxx [149]
The variables are:

Matinee ticket ⇒ We can call this item as 'm'
Drink ⇒ We can call this item as 'd'
A bag of popcorn ⇒ We can call this item as 'p'

One matinee ticket costs 6.50
Two matinee ticket cost 2×6.50
Three matinee ticket cost 3×6.50
'm' matinee ticket cost m × 6.50 = 6.50m

One drink costs 5.50
Two drinks cost 2×5.50
Three drinks cost 3×5.50
'd' drinks cost d×3.50 = 3.50d

One bag of popcorn costs 6
Two bags of popcorn cost 2×6
Three bags of popcorn cost 3×6
'p' bags of popcorn cost p×6 = 6p

The expression for total cost is given by

Total = 6.50m + 3.50d + 6p

7 0
3 years ago
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