Answer:
Step-by-step explanation:
The first thing that you can do is to factor out an x^2 from the expression.
x^2(2x^2+4x-30)
The next step is to factor out a 2.
2x^2(x^2+2x-15)
Finally, you can factor the quadratic inside.
2x^2(x-3)(x+5)
And now you're finished! Hope this helps!
Answer: x = -3/4 can not be a rational zero of the polynomial.
Step-by-step explanation:
We have the polynomial:
6x^5 + ax^3 -bx -12 = 0.
The theorem says that:
If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).
The factors of -12 (different than itself) are (independent of the sign).
1, 2, 3, 4 and 6.
So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.
The factors of 6 are:
1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.
Then the option that can not be a zero of the polynomial is
x = -3/4
because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.
What the heck theyre having you solve for surface area of a cylinder in elementary??
I think it’s 3, i input it all into my calculator. i’m not sure about the exponent tho so probably 3^29
Answer: Elisa
Step-by-step explanation: the first one did 8 withdraws the second one did 5 withdraws
(divide the total by the amount withdrawn each time)
