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3 years ago

Find the value of z such that 0.120.12 of the area lies to the right of z. round your answer to two decimal places.

1 answer:

7 0

The value of x such that 0.12 of the area lies to the right of z will be given by:
1-P(x≤x)=0.12
P(x≤X)=1-0.12=0.88
The z-value corresponding to this value will be:
z=1.18

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Function g can be thought of as a translation (shifted) version of f(x)=x^2

dimaraw [331]

Answer:

(x+5)²

Step-by-step explanation:

To solve this we just need to shift the graph 5 spots to the left

to do this we need to add 5 to the x

(x+5)²

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3 years ago

If something is scarce it is generally

dmitriy555 [2]

Little of, not in plethora, small numbered

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3 years ago

The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangle is 90 cm

svet-max [94.6K]

The sides of the triangle are 3x, 4x and 5x

3x + 4x + 5x = 90
12x = 90
x = 90/12
x = 7.5

first side = 3x = 3 * 7.5 = 22.5 cm
second side = 4x = 4 * 7.5 = 30 cm
third side = 5x = 5*7.5 = 37.5 cm

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3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

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3 years ago

Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's

Tom [10]

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

$=\frac{5}{94}\times 100$

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer

5 0

3 years ago

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