Question

Find the value of z such that 0.120.12 of the area lies to the right of z. round your answer to two decimal places.

Answer 1

The value of x such that 0.12 of the area lies to the right of z will be given by:
1-P(x≤x)=0.12
P(x≤X)=1-0.12=0.88
The z-value corresponding to this value will be:
z=1.18