How many different tables of 4 can you make from 16 potential bridge players? How many different tables if 4 players insist on p
2 answers:
Answer: Hence, a) 1820, b) 495.
Step-by-step explanation:
Since we have given that
Number of potential bridge players = 20
Number of tables = 4
We need to find the number of different tables of 4 from 16 potential bridge players.
So, Number of different ways would be
If 4 players insist on playing together,
remaining players = 16-4 =12
so, Number of different ways would be
Hence, a) 1820, b) 495.
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<h2>Answer:</h2>
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Answer:
The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet
Step-by-step explanation:
At first, let us find the perimeter of the playground
∵ Perimeter of a triangle is P = S1 + S2 + S3
∵ The sides of the triangular playground are (2x) ft, (x - 1) ft, and x ft
∴ S1 = 2x, S2 = x - 1, S3 = x
→ Substitute them in the rule of the perimeter above
∵ P = 2x + x - 1 + x
→ Add the like terms
∴ P = (2x + x + x) - 1
∴ P = 4x - 1
∵ The perimeter of this playground is 27 feet
∴ P = 27
→ Equate the two values of P
∴ 4x - 1 = 27
→ Add 1 to both sides
∴ 4x - 1 + 1 = 27 + 1
∴ 4x = 28
→ Divide both sides by 4
∵ =
∴ x = 7
→ Substitute the value of x in each side to find their lengths
∵ S1 = 2(7)
∴ S1 = 14 feet
∵ S2 = 7 - 1
∴ S2 = 6 feet
∵ S3 = 7 feet
∴ The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet
Option C
<em><u>Solution:</u></em>
We have to solve for "x"
From given,
Solve for brackets
Use distributive property
a(b + c) = ab + ac
Therefore,
Combine the constants
Move the variables to left side of equation
Combine the like terms
Thus option C is correct