Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:
Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:
![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer: E. :)
Step-by-step explanation:
Answer:
Option C (72)
Step-by-step explanation:
In the figure attached we can see a rectangle ABCD with length 12 cm and width 9 cm.
A triangle PEF with height BE and base EF.
Since side AE = 3 cm, so side EB = EC = 9 - 3 = 6cm
and EF = AD = 12 cm
Now we will find the area of of the parts of the card that are not shaded.
Area of parts that are not shaded = Area of rectangle - area of shaded triangle
= (12×9) -
= 108 -
Option c) 72 cm² is the area of non shaded part.
Hope this helps!! -Mina
Domain: (-∞,∞)
Range: (3,∞)
x-intercepts: none
y-intercepts: (0,7)
Interval positive: (3,∞)
Interval negative: none
Interval increasing: (7,∞)
Interval decreasing: (-∞,7)
I'm not sure what the average rate of change over is though.
Ik you asked for one but here's a couple: 1,2,4,8,16,32
