Answer:
wait it keeps timing me ima write my answer in comments
Step-by-step explanation:
Answer:
The interquartile range is 5.
Step-by-step explanation:
Ah, a throwback to interquartile range... let me help :)
4,5,6,8,9,10,11,12
First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.
When a line is reflected along the x axis, the sign of the x coordinate of the points on the line remains the same while that of the y coordinate is reversed. Therefore,
For point A, the x coordinate is - 2 and the y coordinate is - 1. After relection over the x axis, it becomes
(- 2, - -1)
= (- 2, 1)
For point B, the x coordinate is - 1 and the y coordinate is - 3. After relection over the x axis, it becomes
(- 1, - -3)
= (- 1, 3)
The coordinates after reflection are A(- 2, 1), B(- 1, 3)
Answer:
You can only simplify it down to -6y+1
Step-by-step explanation:
Since there is nothing past the equals sign, there is no way to solve it, only a way to simplify it. Hope this helps!
Answer:
A (-1,-2), B (-4,0), C (3,3)
Step-by-step explanation: