<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
9514 1404 393
Answer:
B. Figure B
Step-by-step explanation:
The figure is difficult to read. We assume the height of the pyramid is 9, and the radius of the cylinder is 1.
The pyramid volume is ...
V = 1/3Bh
V = 1/3(4²)(9) = 48 . . . cubic units
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The cylinder volume is ...
V = πr²h
V = π(1²)(48) = 48π . . . cubic units
The cylinder has π times as much volume as the pyramid. Figure B is larger.
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<em>Additional comment</em>
If the diameter (not the radius) of the cylinder is 1 unit, then its volume is 12π cubic units and the pyramid has more volume.
0.015 x 600 =9 so more than expected
I'm not sure about the second image.
But the first one is telling you to translate x, 3 units left, and translate y, 4 units up.
(-6, 0) will turn to (-9, 4)
I subtracted 3 from -6 and added 4 to 0.
