All categories

3 years ago

How to calculate velocity

Mathematics

2 answers:

Alex787 [66]3 years ago

6 0

Answer:

Step-by-step explanation:

In the simplest case, speed is equal to distance traveled / elapsed time. This results in a constant quantity.

v = d/t is the formula applying to that.

zaharov [31]3 years ago

4 0

Answer: Divide the total displacement by the total time.

In order to find the velocity of the moving object, you will need to divide the change in position by the change in time. Specify the direction moved, and you have the average velocity. Example 1 (cont.): The car changed its position by 36 meters over 8 seconds.

You might be interested in

Use the properties of exponents to rewrite y=3e^-0.6t in the form y=a(1+r)^t or y=a(1-r)^t. Round the value or r to the nearest

vesna_86 [32]

Answer:

$y=3(1-0.451)^t$

The value of r is 0.451

The percentage decrease is about 45.1%

Step-by-step explanation:

The given exponential function is $y=3e^{-0.6t}$

Using the exponent rule, $(x)^{ab}=(x^a)^b$

$y=3(e^{-0.6})^t$

Now the value of $e^{-0.6}=0.5488$

Thus, we can rewrite the function as

$y=3(0.5488)^t$

Therefore, the function in form $y=a(1-r)^t$

$y=3(1-0.451)^t$

The value of r is 0.451

The percentage decrease is about 0.451 ×100 = 45.1%

8 0

4 years ago

Carol began with $50 in her bank account and then added an additional $10 a month. Select the algebraic model that describes b,

FrozenT [24]

B = 10m + 50 <========

3 0

3 years ago

Read 2 more answers

Help me please, match the number to the letter

kenny6666 [7]

Answer: 1b 2c 3e? 4d 5a

<u>Step-by-step explanation:</u>

There are 2 items that need to be checked.

The midpoint of the coordinates is the center of the circle
The diameter of the coordinates is the diameter of the circle.

Midpoint:

$Midpoint = \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\1)\ \bigg(\dfrac{-4+2}{2},\dfrac{-1+10}{2}\bigg)=\bigg(\dfrac{-2}{2},\dfrac{9}{2}\bigg)=(-1, 4.5)\implies \text{equation b}\\\\\\2)\ \bigg(\dfrac{1+7}{2},\dfrac{3-10}{2}\bigg)=\bigg(\dfrac{8}{2},\dfrac{-7}{2}\bigg)=(4, -3.5)\implies \text{equation c}\\\\\\3)\ \bigg(\dfrac{4-8}{2},\dfrac{-2+6}{2}\bigg)=\bigg(\dfrac{-4}{2},\dfrac{4}{2}\bigg)=(-2,2 )\implies \text{none of the equations}$

$4)\ \bigg(\dfrac{6-4}{2},\dfrac{3-13}{2}\bigg)=\bigg(\dfrac{2}{2},\dfrac{-10}{2}\bigg)=(1, -5)\implies \text{equation d}\\\\\\5)\ \bigg(\dfrac{7-1}{2},\dfrac{5+8}{2}\bigg)=\bigg(\dfrac{6}{2},\dfrac{13}{2}\bigg)=(3, 6.5)\implies \text{equation a}$

Diameter:

distance between coordinates = 2√r² (from circle equation)

$\text{formula for coordinates is: }d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\1)\ \text{Coordinates: } d=\sqrt{(-4-2)^2+(-1-10)^2}=\sqrt{36+121}=12.5\\b)\ \text{Circle: }2\sqrt{39.25}=12.5\\\\\\2)\ \text{Coordinates: } d=\sqrt{(1-7)^2+(3+10)^2}=\sqrt{36+169}=14.3\\c)\ \text{Circle: }2\sqrt{51.25}=14.3\\\\\\4)\ \text{Coordinates: } d=\sqrt{(6+4)^2+(3+13)^2}=\sqrt{100+256}=18.9\\d)\ \text{Circle: }2\sqrt{89}=18.9$