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Area of a triangle ABC with the given vertices is 3 square units.
Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).
<h3>What is the area of triangle formula in coordinate geometry?</h3>In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.
Area of a triangle =
Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)
Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)
= 1/2 (|3(3)+5(-3)+7(0)|)
= 1/2 (|(9-15)|)
= 1/2 × 6
= 3 square units
Therefore, area of a triangle ABC with the given vertices is 3 square units.
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The inverse functions of sine, cos and tan functions are csc, sec and cot respectively.
<u>Step-by-step explanation:</u>
The reciprocals of sine, cos and tan functions are csc, sec and cot functions. The reciprocal of cosine function is secant, (sec) sec θ =
The inverse or reciprocal function is cosecant (csc),
The inverse tangent function is cotangent (cot) , expressed in two ways: or
So then its reciprocal or inverse is termed as cot θ.