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VikaD [51]
3 years ago
11

72 divide 4176 long division​

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

it would be 58

Step-by-step explanation:

if you do 72 x 417 it would be 5 at the top and 360 would be at the bottom so it would be 417-360 which is 57 and the six at the top u would drop so now it is 576 so if you do 72 x 8 it would be 576 so u would put the 8 with the 5 and subtract the 576 - 576 and that is 0 BOOM

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I don't understand no this at all​
Katena32 [7]

Answer:

Just get the perimeter of the smaller rectangle then times it by 4

Step-by-step explanation:

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8 0
3 years ago
(20pts) I need to know who is incorect and why
svp [43]

Answer:

i thig it is hj

Step-by-step explanation:

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6 0
3 years ago
Aaron is taking a multiple choice test with a total of 20 points available. Each question is worth exactly 1 point. What would b
Ede4ka [16]

Let x represent number of wrong questions answered by Aaron.

We have been given that Aaron is taking a multiple choice test with a total of 20 points available. Each question is worth exactly 1 point. We are asked to find Aaron's score (out of 20) if he got 6 questions wrong.

To find Aaron's score, we will subtract number of wrong answers from total score.

\text{Aaron's score}=\text{Total score}-\text{Number of wrong answers}

\text{Aaron's score}=20-6

\text{Aaron's score}=14

Therefore, Aaron's test scores would be 14 out of 20.

To find Aaron's score if he got x questions wrong, we will subtract x from total scores that is 20-x.

Therefore, Aaron's score would be  20-x, if he got x questions wrong.

4 0
3 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
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Dmitriy789 [7]

Answer:

the answers are : A , B , and E. i just took the assignment.

Step-by-step explanation:

5 0
3 years ago
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